Question

1. let $f(x) = \sqrt{x + 1}$, $g(x) = 2x - 5$, and $h(x) = 3x^2 - 3$. find the indicated value. $g(g(-2.5)) = \square$

Explanation:

Step1: Calculate \( g(-2.5) \)

Given \( g(x) = 2x - 5 \), substitute \( x = -2.5 \) into \( g(x) \):
\( g(-2.5) = 2(-2.5) - 5 = -5 - 5 = -10 \)

Step2: Calculate \( g(g(-2.5)) = g(-10) \)

Substitute \( x = -10 \) into \( g(x) \):
\( g(-10) = 2(-10) - 5 = -20 - 5 = -25 \)

Step3: Calculate \( g(g(g(-2.5))) = g(-25) \)

Substitute \( x = -25 \) into \( g(x) \):
\( g(-25) = 2(-25) - 5 = -50 - 5 = -55 \)

Answer:

\(-55\)