Question

lets practice... who started out faster? who had a constant speed? describe b from 10 - 20 min. find their average speeds. slope = steeper slope= straight line = flat line = name graphing motion time (min) distance (m) 0 10 20 30 200 400 600 800 1000 1200 1400 1600 1800 2000 2200 2400 a b

Explanation:

Step1: Determine who started faster

By observing the starting - point of the graphs, the line for bug A has a steeper slope at the start. So bug A started out faster.

Step2: Identify who had a constant speed

A constant - speed is represented by a straight - line on a distance - time graph. Bug A has a straight - line throughout, so bug A had a constant speed.

Step3: Describe bug B from 10 - 20 min

From 10 - 20 min, the distance of bug B does not change, which means bug B was stationary.

Step4: Calculate average speeds

The total time for both bugs is 30 min. Bug A travels 2400 m in 30 min. The average speed of bug A, $v_A=\frac{2400}{30}=80$ m/min. Bug B travels 1200 m in 30 min. The average speed of bug B, $v_B = \frac{1200}{30}=40$ m/min.

Answer:

1. Who started out faster? A. Bug A
2. Who had a constant speed? A. Bug A
3. Describe B from 10 - 20 min: Bug B was stationary.
4. Find their average speeds: Bug A: 80 m/min, Bug B: 40 m/min