Question

light wave a has a greater frequency than light wave b. which has a greater wavelength? answer: a. wave a b. wave b c. wave a and wave b are equal d. not enough information is given.

Explanation:

Step1: Recall wave - frequency relationship

The relationship between the speed of light ($c$), wavelength ($\lambda$) and frequency ($f$) is $c = \lambda f$. Since the speed of light in a vacuum is constant ($c$ is a constant value), wavelength and frequency are inversely proportional, i.e., $\lambda=\frac{c}{f}$.

Step2: Analyze given frequency information

Given that light wave A has a greater frequency than light wave B, i.e., $f_A>f_B$. Using the formula $\lambda=\frac{c}{f}$, when $c$ is constant, a higher frequency corresponds to a shorter wavelength. So $\lambda_A<\lambda_B$.

Answer:

C. Wave B