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linear systems graphing a system of two linear inequalities: advanced (…

Question

linear systems
graphing a system of two linear inequalities: advanced
(a) graph the solution to the following system of inequalities.
\

$$\begin{cases} 7x + 4y \\leq -4 \\\\ y > -\\dfrac{7}{4}x - 7 \\end{cases}$$

graph grid
(b) give the coordinates of one point in the solution set.
point in the solution set: (\square, \square)

Explanation:

Response
Part (a) Graphing the System of Inequalities
Step 1: Analyze the first inequality \(7x + 4y \leq -4\)
  • Rewrite it in slope - intercept form (\(y=mx + b\)):
  • Subtract \(7x\) from both sides: \(4y\leq - 7x-4\).
  • Divide both sides by 4: \(y\leq-\frac{7}{4}x - 1\).
  • The boundary line is \(y =-\frac{7}{4}x - 1\) (a straight line with slope \(m =-\frac{7}{4}\) and \(y\) - intercept \(b=-1\)). Since the inequality is \(\leq\), the line is solid, and we shade the region below the line.
Step 2: Analyze the second inequality \(y>-\frac{7}{4}x - 7\)
  • The boundary line is \(y =-\frac{7}{4}x - 7\) (a straight line with slope \(m =-\frac{7}{4}\) and \(y\) - intercept \(b = - 7\)). Since the inequality is \(>\), the line is dashed, and we shade the region above the line.
Step 3: Find the overlapping region
  • The two lines \(y =-\frac{7}{4}x - 1\) and \(y=-\frac{7}{4}x - 7\) are parallel (same slope). The solution to the system is the region that is below the solid line \(y =-\frac{7}{4}x - 1\) and above the dashed line \(y=-\frac{7}{4}x - 7\).
Part (b) Finding a Point in the Solution Set
Step 1: Choose a value for \(x\)

Let's choose \(x = 0\).

Step 2: Check the first inequality \(7x + 4y\leq - 4\)

Substitute \(x = 0\) into \(7x+4y\leq - 4\):

  • \(7(0)+4y\leq - 4\), which simplifies to \(4y\leq - 4\), or \(y\leq - 1\).
Step 3: Check the second inequality \(y>-\frac{7}{4}x - 7\)

Substitute \(x = 0\) into \(y>-\frac{7}{4}x - 7\):

  • \(y> - 7\).
Step 4: Find a \(y\) - value that satisfies both

We need \(y\) such that \(-7Check if \((0,-2)\) satisfies both inequalities:

  • For \(7x + 4y\leq - 4\): \(7(0)+4(-2)=-8\leq - 4\) (true).
  • For \(y>-\frac{7}{4}x - 7\): \(-2>-\frac{7}{4}(0)-7=-7\) (true).

Answer:

(a) The graph has a solid line \(y =-\frac{7}{4}x - 1\) (shade below) and a dashed line \(y=-\frac{7}{4}x - 7\) (shade above), with the overlapping region as the solution.
(b) One point in the solution set is \((0, - 2)\) (other valid points like \((-4, - 5)\) etc. are also correct).