Question

lines from point/slope (diagonal only)score: 1/5 penalty: nonequestionwhat is the equation of the line that passes through the point $(-1,8)$ and has a slope of $-6$?show examplesanswer attempt 1 out of 2submit answer

Explanation:

Step1: Recall point-slope formula

The point-slope form of a line is $y - y_1 = m(x - x_1)$, where $m$ is the slope, and $(x_1, y_1)$ is the given point.

Step2: Substitute given values

Here, $m = -6$, $x_1 = -1$, $y_1 = 8$. Substitute into the formula:
$y - 8 = -6(x - (-1))$
Simplify the right-hand side:
$y - 8 = -6(x + 1)$

Step3: Convert to slope-intercept form (optional, standard)

Expand and isolate $y$:
$y - 8 = -6x - 6$
$y = -6x - 6 + 8$
$y = -6x + 2$

Answer:

$y = -6x + 2$ (or $y - 8 = -6(x + 1)$)