Question

look at this diagram: if $overleftrightarrow{gi}$ and $overleftrightarrow{jl}$ are parallel lines and $mangle jkm = 140^{circ}$, what is $mangle jkh?$

Explanation:

Step1: Recall linear - pair property

Linear - pair angles are supplementary, meaning they add up to 180°. $\angle JKM$ and $\angle JKH$ form a linear pair.

Step2: Set up the equation

Let $m\angle JKH=x$. We know that $m\angle JKM + m\angle JKH=180^{\circ}$. Given $m\angle JKM = 140^{\circ}$, the equation is $140^{\circ}+x = 180^{\circ}$.

Step3: Solve for $x$

Subtract 140° from both sides of the equation: $x=180^{\circ}- 140^{\circ}$.
$x = 40^{\circ}$.

Answer:

$40$