Question

look at this diagram: if \\(\overleftrightarrow{ce}\\) and \\(\overleftrightarrow{fh}\\) are parallel lines and \\(m\angle fgi = 140^\circ\\), what is \\(m\angle cdb\\)? \\(\square^\circ\\)

Explanation:

Step1: Find supplementary angle of ∠FGI

$\angle FGI + \angle FGD = 180^\circ$
$\angle FGD = 180^\circ - 140^\circ = 40^\circ$

Step2: Use parallel lines property

Since $\overleftrightarrow{CE} \parallel \overleftrightarrow{FH}$, $\angle CDB = \angle FGD$ (corresponding angles are congruent)
$\angle CDB = 40^\circ$

Answer:

$40$