Question

look at the table you completed. which wave transmits more energy per second?

Explanation:

Step1: Determine amplitude

The amplitude of a wave is the maximum displacement from the equilibrium position. From the graphs, the maximum displacement of Wave 1 is 4 cm and of Wave 2 is 2 cm. So, amplitude is greater for Wave 1.

Step2: Determine frequency

The frequency is the number of complete - cycles per unit length. In the given position - displacement graphs, in the same horizontal length, Wave 2 has more number of cycles than Wave 1. So, frequency is greater for Wave 2.

Step3: Determine energy per second

The energy per second of a wave is proportional to the square of its amplitude and its frequency ($E\propto A^{2}f$). Wave 1 has a larger amplitude ($A_1 = 4$ cm) and Wave 2 has a higher frequency. But since the amplitude of Wave 1 is twice that of Wave 2 and energy is proportional to the square of the amplitude, the contribution of amplitude to energy is more significant. So, Wave 1 transmits more energy per second.

Answer:

The amplitude is greater for Wave 1.
The frequency is greater for Wave 2.
Wave 1 transmits more energy per second.