Question

looking up, jim sees two hot - air balloons in the sky as shown. he determines that the lower hot - air balloon is 670 meters away, at an angle of 42° from the vertical. the higher hot - air balloon is 945 meters away, at an angle of 36° from the vertical. how much higher is the balloon on the right than the balloon on the left? do not round any intermediate computations. round your answer to the nearest tenth. note that the figure below is not drawn to scale.

Explanation:

Step1: Find height of lower balloon

$h_1 = 670\times\cos42^{\circ}$

Step2: Find height of higher balloon

$h_2 = 945\times\cos36^{\circ}$

Step3: Find height difference

$\Delta h=h_2 - h_1=945\times\cos36^{\circ}-670\times\cos42^{\circ}$

Answer:

$246.8$