Question

loris family is on a road trip. they split their drive into the five legs listed in the table. find the average velocity for each leg of the trip. then arrange the legs of the trip from lowest velocity to highest.

leg	distance (km)	time (min)
b	20	15
c	24	12
d	36	9
e	14	14

Explanation:

Step1: Recall velocity formula

The formula for average velocity $v=\frac{d}{t}$, where $d$ is distance and $t$ is time. We need to convert time from minutes to hours since velocity is usually in km/h. 1 hour = 60 minutes.

Step2: Calculate velocity for Leg A

$t_A = 10\ min=\frac{10}{60}h=\frac{1}{6}h$, $d_A = 15\ km$. Then $v_A=\frac{d_A}{t_A}=\frac{15}{\frac{1}{6}} = 90\ km/h$.

Step3: Calculate velocity for Leg B

$t_B=15\ min=\frac{15}{60}h = \frac{1}{4}h$, $d_B = 20\ km$. Then $v_B=\frac{d_B}{t_B}=\frac{20}{\frac{1}{4}}=80\ km/h$.

Step4: Calculate velocity for Leg C

$t_C = 12\ min=\frac{12}{60}h=\frac{1}{5}h$, $d_C = 24\ km$. Then $v_C=\frac{d_C}{t_C}=\frac{24}{\frac{1}{5}} = 120\ km/h$.

Step5: Calculate velocity for Leg D

$t_D=9\ min=\frac{9}{60}h=\frac{3}{20}h$, $d_D = 36\ km$. Then $v_D=\frac{d_D}{t_D}=\frac{36}{\frac{3}{20}}=240\ km/h$.

Step6: Calculate velocity for Leg E

$t_E = 14\ min=\frac{14}{60}h=\frac{7}{30}h$, $d_E = 14\ km$. Then $v_E=\frac{d_E}{t_E}=\frac{14}{\frac{7}{30}} = 60\ km/h$.

Step7: Arrange velocities from lowest to highest

The order is: Leg E ($60\ km/h$), Leg B ($80\ km/h$), Leg A ($90\ km/h$), Leg C ($120\ km/h$), Leg D ($240\ km/h$).

Answer:

Leg E: 60 km/h, Leg B: 80 km/h, Leg A: 90 km/h, Leg C: 120 km/h, Leg D: 240 km/h