Question

1. a man hits a golf - ball (0.042kg) which accelerates at a rate of 20 m/s². what amount of force acted on the ball?

Explanation:

Step1: Identify the formula

Use Newton's second - law $F = ma$.

Step2: Substitute the values

Given $m = 0.042\ kg$ and $a=20\ m/s^{2}$, then $F=(0.042\ kg)\times(20\ m/s^{2})$.

Step3: Calculate the force

$F = 0.84\ N$.

Answer:

$0.84\ N$