Question

martin puts two bowls of fruit out for his friends. the bowl of grapes has 9 green grapes and 16 red grapes. the bowl of tangerines has 7 seeded and 3 seedless tangerines. martin’s friend chooses a random grape and a random tangerine. what is the probability that she chooses a green grape and a seedless tangerine? enter the answer in the box.

Explanation:

Step1: Calculate total grapes

Total grapes = 9 (green) + 16 (red) = 25.
Probability of green grape: $\frac{9}{25}$.

Step2: Calculate total tangerines

Total tangerines = 7 (seeded) + 3 (seedless) = 10.
Probability of seedless tangerine: $\frac{3}{10}$.

Step3: Multiply probabilities (independent events)

Probability (green grape and seedless tangerine) = $\frac{9}{25} \times \frac{3}{10} = \frac{27}{250}$.

Answer:

$\frac{27}{250}$