Question

martin puts two bowls of fruit out for his friends. the bowl of grapes has 9 green grapes and 16 red grapes. the bowl of tangerines has 7 seeded and 3 seedless tangerines. martins friend chooses a random grape and a random tangerine. what is the probability that she chooses a green grape and a seedless tangerine? enter the answer in the box.

Explanation:

Step1: Calculate total number of grapes

Total grapes = 9 (green) + 16 (red) = 25.

Step2: Calculate probability of choosing a green grape

Probability of green grape $P(G)=\frac{9}{25}$.

Step3: Calculate total number of tangerines

Total tangerines = 7 (seeded) + 3 (seedless) = 10.

Step4: Calculate probability of choosing a seedless tangerine

Probability of seedless tangerine $P(S)=\frac{3}{10}$.

Step5: Calculate the combined probability

Since the events are independent, the probability of both events happening is the product of their probabilities. So $P = P(G)\times P(S)=\frac{9}{25}\times\frac{3}{10}=\frac{27}{250}$.

Answer:

$\frac{27}{250}$