Question

match each pair of angle measures of a triangle with the remaining angle measure. 96 degrees and 51 degrees 16 degrees and 102 degrees 119 degrees and 23 degrees 28 degrees and 87 degrees 65 degrees 33 degrees 38 degrees 62 degrees

Explanation:

1. Recall that the sum of the interior - angles of a triangle is 180 degrees.

• For the pair 96 degrees and 51 degrees:
• Let the third angle be \(x\). Then \(x = 180-(96 + 51)=180 - 147=33\) degrees.
• For the pair 16 degrees and 102 degrees:
• Let the third angle be \(y\). Then \(y = 180-(16 + 102)=180 - 118 = 62\) degrees.
• For the pair 119 degrees and 23 degrees:
• Let the third angle be \(z\). Then \(z=180-(119 + 23)=180 - 142 = 38\) degrees.
• For the pair 28 degrees and 87 degrees:
• Let the third angle be \(w\). Then \(w = 180-(28 + 87)=180 - 115 = 65\) degrees.

Answer:

96 degrees and 51 degrees → 33 degrees
16 degrees and 102 degrees → 62 degrees
119 degrees and 23 degrees → 38 degrees
28 degrees and 87 degrees → 65 degrees