Question

match the graph with its function y=-x²

Explanation:

Step1: Identify parabola direction

The function is $y=-x^2$. For quadratic functions $y=ax^2$, if $a<0$, the parabola opens downward. Here $a=-1<0$, so it opens downward.

Step2: Check vertex and points

The vertex of $y=-x^2$ is at $(0,0)$. Test $x=2$: $y=-(2)^2=-4$, so the point $(2,-4)$ lies on the graph. This matches the downward-opening parabola in option A.

Answer:

A. The downward-opening parabola with vertex at (0,0) passing through (2,-4) and (-2,-4)