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Question
math ii miller - 5th period
4.3 one and two - step equations
question 10 (1 point)
solve.
\\(\frac{x}{-3}+12 = 10\\)
x=
blank 1:
review answers back
Step1: Subtract 12 from both sides
$\frac{x}{-3} + 12 - 12 = 10 - 12$
$\frac{x}{-3} = -2$
Step2: Multiply both sides by -3
$\frac{x}{-3} \times (-3) = -2 \times (-3)$
$x = 6$
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