Question

1)
2)
3)
4)

Explanation:

To solve for the area of each trapezoid, we use the formula for the area of a trapezoid: \( A = \frac{1}{2}(b_1 + b_2)h \), where \( b_1 \) and \( b_2 \) are the lengths of the two parallel sides (bases) and \( h \) is the height (the perpendicular distance between the bases).

1) Trapezoid with \( b_1 = 1.5 \) in, \( b_2 = 3.3 \) in, \( h = 2.9 \) in

Step 1: Identify the formula

The area of a trapezoid is \( A = \frac{1}{2}(b_1 + b_2)h \).

Step 2: Substitute the values

Substitute \( b_1 = 1.5 \), \( b_2 = 3.3 \), and \( h = 2.9 \) into the formula:
\( A = \frac{1}{2}(1.5 + 3.3)(2.9) \)

Step 3: Simplify the expression

First, add the bases: \( 1.5 + 3.3 = 4.8 \)
Then, multiply by the height: \( 4.8 \times 2.9 = 13.92 \)
Finally, multiply by \( \frac{1}{2} \): \( \frac{1}{2} \times 13.92 = 6.96 \)

Answer:

(1): \( 6.96 \) square inches

2) Trapezoid with \( b_1 = 0.6 \) in, \( b_2 = 2 \) in, \( h = 2 \) in

Step 1: Identify the formula

\( A = \frac{1}{2}(b_1 + b_2)h \)

Step 2: Substitute the values

Substitute \( b_1 = 0.6 \), \( b_2 = 2 \), and \( h = 2 \):
\( A = \frac{1}{2}(0.6 + 2)(2) \)

Step 3: Simplify the expression

Add the bases: \( 0.6 + 2 = 2.6 \)
Multiply by the height: \( 2.6 \times 2 = 5.2 \)
Multiply by \( \frac{1}{2} \): \( \frac{1}{2} \times 5.2 = 2.6 \)