Question

1. $y = 3(x - 2)^2 - 3$

v:( , ) a.s:

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a parabola is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex (\(V\)) and the axis of symmetry (AS) is \( x = h \).

Step2: Identify \(h\) and \(k\) from given equation

Given \( y = 3(x - 2)^2 - 3 \), compare with \( y = a(x - h)^2 + k \). Here, \( h = 2 \) and \( k = - 3 \).

Step3: Determine vertex and axis of symmetry

• Vertex (\(V\)): Using \( h = 2 \) and \( k = - 3 \), the vertex is \((2, - 3)\).
• Axis of Symmetry (AS): Using \( h = 2 \), the axis of symmetry is \( x = 2 \).

Answer:

Vertex \( V:(2, - 3) \), Axis of Symmetry \( AS: x = 2 \)