Question

1. $2x^2 - 8x + 6$

Explanation:

Step1: Factor out the common factor 2

$2x^{2}-8x + 6=2(x^{2}-4x + 3)$

Step2: Factor the quadratic expression inside the parentheses

We need to find two numbers that multiply to 3 and add up to - 4. The numbers are -1 and -3. So $x^{2}-4x + 3=(x - 1)(x - 3)$

Step3: Combine the factors

Putting it all together, we get $2(x - 1)(x - 3)$

Answer:

$2(x - 1)(x - 3)$