Question

$^2 + 8x - 11$, $g(x) = 14 - \frac{2}{3}x$, and $h(x) = -x - 7$

1. $g(9) + h(-14)$

Explanation:

Step1: Calculate \( g(9) \)

Substitute \( x = 9 \) into \( g(x)=14 - \frac{2}{3}x \):
\( g(9)=14-\frac{2}{3}\times9 \)
\( =14 - 6 \)
\( = 8 \)

Step2: Calculate \( h(-14) \)

Substitute \( x=-14 \) into \( h(x)=-x - 7 \):
\( h(-14)=-(-14)-7 \)
\( =14 - 7 \)
\( = 7 \)

Step3: Calculate \( g(9)+h(-14) \)

Add the results from Step1 and Step2:
\( g(9)+h(-14)=8 + 7 \)
\( = 15 \)

Answer:

\( 15 \)