Question

1. $x^3 - 3x^2 - 28x$

Explanation:

Step1: Factor out common term $x$

$x^3 - 3x^2 - 28x = x(x^2 - 3x - 28)$

Step2: Factor quadratic trinomial

Find two numbers that multiply to $-28$ and add to $-3$: $-7$ and $4$.
$x^2 - 3x - 28 = (x - 7)(x + 4)$

Step3: Combine factors

$x(x^2 - 3x - 28) = x(x - 7)(x + 4)$

Answer:

$x(x - 7)(x + 4)$