Question

$(2t - 4)^2$

Explanation:

Step1: Recall square of difference formula

The formula for $(a-b)^2$ is $a^2 - 2ab + b^2$. Here, $a=2t$, $b=4$.

Step2: Calculate each term

First term: $(2t)^2 = 4t^2$
Second term: $-2*(2t)*4 = -16t$
Third term: $4^2 = 16$

Step3: Combine the terms

Add the three calculated terms together.
$4t^2 - 16t + 16$

Answer:

$4t^2 - 16t + 16$