Question

3 + (4x²y⁹z⁷)⁰

Explanation:

Step1: Recall the zero exponent rule

Any non - zero number raised to the power of 0 is 1. So, for the term \((4x^{2}y^{9}z^{7})^{0}\), since the base \(4x^{2}y^{9}z^{7}\) is non - zero (assuming \(x\), \(y\), \(z\) are such that the base is not zero), \((4x^{2}y^{9}z^{7})^{0}=1\).

Step2: Add the two terms

We have the expression \(3+(4x^{2}y^{9}z^{7})^{0}\). Substituting the value of \((4x^{2}y^{9}z^{7})^{0}\) from Step 1, we get \(3 + 1\).

Step3: Calculate the sum

\(3+1 = 4\).

Answer:

\(4\)