Question

1. $f(x)=\

$$\begin{cases}-2x + 1&x\\leq2\\5x - 4&x>2\\end{cases}$$

$ $(2, - 3)$ $(2,6)$ $f(-4)=-2(-4)+1$ $f(8)=5(8)-4$ $f(2)=-2(2)+1$

Explanation:

Step1: Evaluate f(-4)

Since -4 ≤ 2, use f(x)=-2x + 1.
$f(-4)=-2\times(-4)+1=8 + 1=9$

Step2: Evaluate f(8)

Since 8>2, use f(x)=5x - 4.
$f(8)=5\times8-4=40 - 4=36$

Step3: Evaluate f(2)

Since 2 ≤ 2, use f(x)=-2x + 1.
$f(2)=-2\times2+1=-4 + 1=-3$

Answer:

$f(-4)=9$, $f(8)=36$, $f(2)=-3$