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Question
- $sqrt{\frac{9}{16}} = pm \boxed{\quad} \\\\$4. $sqrt3{27} = \boxed{\quad}$
Step1: Simplify square root of fraction
$\sqrt{\frac{9}{16}} = \frac{\sqrt{9}}{\sqrt{16}} = \frac{3}{4}$
Step2: Identify square root solutions
The square root has two solutions: $\pm\frac{3}{4}$
Step3: Simplify cube root of 27
$\sqrt[3]{27} = 3$, since $3^3=27$
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- $\boldsymbol{\frac{3}{4}}$ (top box), $\boldsymbol{\frac{3}{4}}$ (bottom box)
- $\boldsymbol{3}$