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3. $y = \\frac{3}{4}x + 7$; domain = $\\{-8, -4, 12\\}$

Question

  1. $y = \frac{3}{4}x + 7$; domain = $\\{-8, -4, 12\\}$

Explanation:

Step1: Substitute $x=-8$

$y = \frac{3}{4}(-8) + 7 = -6 + 7 = 1$

Step2: Substitute $x=-4$

$y = \frac{3}{4}(-4) + 7 = -3 + 7 = 4$

Step3: Substitute $x=12$

$y = \frac{3}{4}(12) + 7 = 9 + 7 = 16$

Answer:

The range corresponding to the given domain is $\{1, 4, 16\}$