Question

$(3x^2 + 2x - 5)(2x - 3)$

Explanation:

Step1: Distribute $3x^2$ to $(2x-3)$

$3x^2 \cdot 2x - 3x^2 \cdot 3 = 6x^3 - 9x^2$

Step2: Distribute $2x$ to $(2x-3)$

$2x \cdot 2x - 2x \cdot 3 = 4x^2 - 6x$

Step3: Distribute $-5$ to $(2x-3)$

$-5 \cdot 2x -5 \cdot (-3) = -10x + 15$

Step4: Combine all terms

$6x^3 - 9x^2 + 4x^2 - 6x - 10x + 15$

Step5: Combine like terms

$6x^3 + (-9x^2+4x^2) + (-6x-10x) + 15 = 6x^3 -5x^2 -16x +15$

Answer:

$6x^3 - 5x^2 - 16x + 15$