Question

1. \\(\

$$\begin{array}{r}\\frac{3}{4}\\\\ -\\frac{2}{5}\\\\ \\hline\\end{array}$$

\\) 6. \\(\

$$\begin{array}{r}\\frac{4}{3}\\\\ -\\frac{2}{5}\\\\ \\hline\\end{array}$$

\\) 7. \\(\

$$\begin{array}{r}\\frac{8}{8}\\\\ -\\frac{4}{9}\\\\ \\hline\\end{array}$$

\\) 8. \\(\

$$\begin{array}{r}\\frac{17}{18}\\\\ -\\frac{2}{3}\\\\ \\hline\\end{array}$$

\\)

Explanation:

Problem 5:

Step1: Find a common denominator

The denominators are 4 and 5. The least common denominator (LCD) of 4 and 5 is \( 4\times5 = 20 \).

Step2: Rewrite the fractions with the LCD

\( \frac{3}{4}=\frac{3\times5}{4\times5}=\frac{15}{20} \) and \( \frac{2}{5}=\frac{2\times4}{5\times4}=\frac{8}{20} \).

Step3: Subtract the fractions

\( \frac{15}{20}-\frac{8}{20}=\frac{15 - 8}{20}=\frac{7}{20} \).

Step1: Find a common denominator

The denominators are 3 and 5. The LCD of 3 and 5 is \( 3\times5 = 15 \).

Step2: Rewrite the fractions with the LCD

\( \frac{4}{3}=\frac{4\times5}{3\times5}=\frac{20}{15} \) and \( \frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15} \).

Step3: Subtract the fractions

\( \frac{20}{15}-\frac{6}{15}=\frac{20 - 6}{15}=\frac{14}{15} \).

Step1: Simplify \( \frac{8}{8} \)

\( \frac{8}{8}=1 \).

Step2: Subtract \( \frac{4}{9} \) from 1

Rewrite 1 as \( \frac{9}{9} \), then \( \frac{9}{9}-\frac{4}{9}=\frac{9 - 4}{9}=\frac{5}{9} \).

Answer:

\( \frac{7}{20} \)

Problem 6: