Question

1. $-2 \geq 4p + 6 + 4$
2. $33 + 4x \leq -(x + 7)$

Explanation:

Step1: Simplify right-hand side (Q6)

$-2 \geq 4p + 10$

Step2: Isolate term with $p$ (Q6)

$-2 - 10 \geq 4p$
$-12 \geq 4p$

Step3: Solve for $p$ (Q6)

$\frac{-12}{4} \geq p$
$p \leq -3$

Step4: Expand right-hand side (Q8)

$33 + 4x \leq -x - 7$

Step5: Isolate terms with $x$ (Q8)

$4x + x \leq -7 - 33$
$5x \leq -40$

Step6: Solve for $x$ (Q8)

$x \leq \frac{-40}{5}$
$x \leq -8$

Answer:

1. For $-2 \geq 4p + 6 + 4$: $p \leq -3$

(On the number line, plot a closed dot at $-3$ and shade all values to the left.)

1. For $33 + 4x \leq -(x + 7)$: $x \leq -8$

(On the number line, plot a closed dot at $-8$ and shade all values to the left.)