Question

1. $(-2x^{3}y^{5})(-4y^{2})(-4x^{4}y)$

Explanation:

Step1: Multiply the coefficients

$(-2) \times (-4) \times (-4) = -32$

Step2: Combine $x$ terms (add exponents)

$x^3 \times x^4 = x^{3+4} = x^7$

Step3: Combine $y$ terms (add exponents)

$y^5 \times y^2 \times y = y^{5+2+1} = y^8$

Step4: Multiply all results together

$-32 \times x^7 \times y^8$

Answer:

$-32x^7y^8$