Question

add.
$(-2t^{3}-4t^{2}-6t - 8)+(4t - 7)$

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. The first polynomial is \(-2t^{3}-4t^{2}-6t - 8\) and the second is \(4t-7\). So we have \(-2t^{3}-4t^{2}-6t - 8+4t-7\).

Step2: Combine like terms

• For the \(t\) terms: \(-6t + 4t=-2t\)
• For the constant terms: \(-8-7 = -15\)
• The terms with \(t^{3}\) and \(t^{2}\) remain as they are since there are no like terms to combine with them.

Putting it all together, we get \(-2t^{3}-4t^{2}-2t - 15\).

Answer:

\(-2t^{3}-4t^{2}-2t - 15\)