Question

add.
$-6\frac{3}{5} + 8 = square$

Explanation:

Step1: Rewrite the expression

We can rewrite the addition of a mixed number and an integer as the sum of the integer part and the fractional part with the integer. So, \(-6\frac{3}{5}+8 = 8 - 6\frac{3}{5}\).

Step2: Subtract the mixed number from the integer

First, we can write \(8\) as \(7\frac{5}{5}\) (since \(8 = 7 + 1\) and \(1=\frac{5}{5}\)). Then we subtract \(6\frac{3}{5}\) from \(7\frac{5}{5}\).
Subtracting the integer parts: \(7 - 6=1\).
Subtracting the fractional parts: \(\frac{5}{5}-\frac{3}{5}=\frac{2}{5}\).

Step3: Combine the results

Combining the integer part and the fractional part, we get \(1+\frac{2}{5}=1\frac{2}{5}\) (or \(\frac{7}{5}\)).

Answer:

\(1\frac{2}{5}\) (or \(\frac{7}{5}\))