Question

add.
$(8n^{4}+4n^{3}+6n^{2}+7n + 1)+(8n^{4}+6n^{2}+9n + 7)$

Explanation:

Step1: Remove parentheses

Remove the parentheses of the two polynomials, we get: \(8n^{4}+4n^{3}+6n^{2}+7n + 1+8n^{4}+6n^{2}+9n + 7\)

Step2: Combine like terms

• For the \(n^{4}\) terms: \(8n^{4}+8n^{4}=16n^{4}\)
• For the \(n^{3}\) terms: \(4n^{3}\) (no other \(n^{3}\) terms to combine with)
• For the \(n^{2}\) terms: \(6n^{2}+6n^{2}=12n^{2}\)
• For the \(n\) terms: \(7n + 9n=16n\)
• For the constant terms: \(1 + 7=8\)

Combine all the combined terms together: \(16n^{4}+4n^{3}+12n^{2}+16n + 8\)

Answer:

\(16n^{4}+4n^{3}+12n^{2}+16n + 8\)