Question

evaluate $\frac{x - y}{x + 3y}$ for $x = 3$ and $y = -2$.

Explanation:

Step1: Substitute values

Substitute $x = 3$ and $y=-2$ into $\frac{x - y}{x + 3y}$.
$\frac{3-(-2)}{3+3\times(-2)}$

Step2: Simplify numerator and denominator

Simplify the numerator $3-(-2)=3 + 2=5$, and the denominator $3+3\times(-2)=3-6=-3$.
So we get $\frac{5}{-3}=-\frac{5}{3}$

Answer:

$-\frac{5}{3}$