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Question
find: \sin v
Step1: Recall sine definition
In a right triangle, $\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}$.
Step2: Identify sides for $\angle V$
For $\angle V$, opposite side to $V$ is $TU$, hypotenuse is $TV = 26$. First, find $TU$ using Pythagoras: $TU=\sqrt{TV^2 - VU^2}=\sqrt{26^2 - 10^2}=\sqrt{676 - 100}=\sqrt{576}=24$.
Step3: Calculate $\sin V$
$\sin V=\frac{TU}{TV}=\frac{24}{26}=\frac{12}{13}$.
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$\frac{12}{13}$