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Question
(\frac{1}{6}(b + 12) = 4)
Step1: Multiply both sides by 6
To eliminate the fraction, we multiply both sides of the equation $\frac{1}{6}(b + 12)=4$ by 6. This gives us $6\times\frac{1}{6}(b + 12)=4\times6$. Simplifying both sides, we get $b + 12 = 24$.
Step2: Subtract 12 from both sides
Now, we want to isolate $b$. So we subtract 12 from both sides of the equation $b + 12 = 24$. That is $b+12 - 12=24 - 12$. Simplifying, we find $b = 12$.
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$b = 12$