$-\frac{4.9^{2}}{4}+3(4.9)+7=$

$-\frac{4.9^{2}}{4}+3(4.9)+7=$

First, we need to find the value of $4.9^2$. $4.9^2 = 4.9\times4.9 = 24.01$

Next, we calculate $-\frac{4.9^2}{4}$, substituting the value of $4.9^2$ we found: $-\frac{24.01}{4}=- 6.0025$

Then, we calculate $3\times4.9 = 14.7$

Now, we add the three terms together: $-6.0025+14.7 + 7$
First, $-6.0025+14.7=8.6975$
Then, $8.6975 + 7=15.6975$

$15.6975$