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$\\frac{b}{5}+9<10$

Question

$\frac{b}{5}+9<10$

Explanation:

Step1: Subtract 9 from both sides

$\frac{b}{5} + 9 - 9 < 10 - 9$
$\frac{b}{5} < 1$

Step2: Multiply both sides by 5

$\frac{b}{5} \times 5 < 1 \times 5$
$b < 5$

Step3: Graph the inequality

On the number line, draw an open circle at 5, then shade all values to the left of 5 (since $b$ is less than 5, not less than or equal to 5).

Answer:

$b < 5$
(Graph: Open circle at 5, arrow pointing left on the number line)