Question

(\frac{\frac{2}{3}x^{3/2}}{-4x}) =

Explanation:

Step1: Simplify the fraction by canceling x (x ≠ 0)

$\frac{3x}{-4x} = \frac{3\cancel{x}}{-4\cancel{x}}$

Step2: Simplify the remaining fraction

$\frac{3}{-4} = -\frac{3}{4}$

Answer:

$-\frac{3}{4}$ (for $x
eq 0$)