Question

$\frac{x}{3}-6 \geq -4$
$\underline{\quad +6 \quad +6}$
$\frac{x}{3} \geq \square$

Explanation:

Step1: Add 6 to both sides

$\frac{x}{3} - 6 + 6 \geq -4 + 6$

Step2: Simplify both sides

$\frac{x}{3} \geq 2$

Answer:

$2$