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Question
g) \\(\frac{10}{5} \cdot -1 - (3^2 + 9 \cdot 2^0) \div 2\\)
Step1: Calculer les puissances
$3^2=9$, $2^0=1$
Step2: Simplifier la fraction
$\frac{10}{5}=2$
Step3: Calculer le produit initial
$2 \cdot (-1) = -2$
Step4: Calculer le contenu des parenthèses
$9 + 9 \cdot 1 = 9 + 9 = 18$
Step5: Diviser par 2
$18 \div 2 = 9$
Step6: Effectuer la soustraction finale
$-2 - 9 = -11$
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$-11$