Question

k. $2x + 9 = 17$
u. $-5 = \frac{x}{3} - 8$
e. $95 = -8x + 7$
t. $\frac{x}{-6} + 17 = 14$
g. $25 = 21 - 4x$

Explanation:

Let's solve each equation one by one:

Equation K: \( 2x + 9 = 17 \)

Step 1: Subtract 9 from both sides

To isolate the term with \( x \), we subtract 9 from both sides of the equation.
\( 2x + 9 - 9 = 17 - 9 \)
\( 2x = 8 \)

Step 2: Divide by 2

To solve for \( x \), we divide both sides by 2.
\( \frac{2x}{2} = \frac{8}{2} \)
\( x = 4 \)

Equation U: \( -5 = \frac{x}{3} - 8 \)

Step 1: Add 8 to both sides

To isolate the term with \( x \), we add 8 to both sides.
\( -5 + 8 = \frac{x}{3} - 8 + 8 \)
\( 3 = \frac{x}{3} \)

Step 2: Multiply by 3

To solve for \( x \), we multiply both sides by 3.
\( 3 \times 3 = \frac{x}{3} \times 3 \)
\( x = 9 \)

Equation E: \( 95 = -8x + 7 \)

Step 1: Subtract 7 from both sides

To isolate the term with \( x \), we subtract 7 from both sides.
\( 95 - 7 = -8x + 7 - 7 \)
\( 88 = -8x \)

Step 2: Divide by -8

To solve for \( x \), we divide both sides by -8.
\( \frac{88}{-8} = \frac{-8x}{-8} \)
\( x = -11 \)

Equation T: \( \frac{x}{-6} + 17 = 14 \)

Answer:

s:

• For K: \( x = 4 \)
• For U: \( x = 9 \)
• For E: \( x = -11 \)
• For T: \( x = 18 \)
• For G: \( x = -1 \)