Question

simplify.
$2^{\frac{1}{3}} \cdot 4^{\frac{1}{3}}$

Explanation:

Step1: Rewrite 4 as power of 2

$4 = 2^2$, so $4^{\frac{1}{3}} = (2^2)^{\frac{1}{3}}$

Step2: Simplify the exponent

$(2^2)^{\frac{1}{3}} = 2^{\frac{2}{3}}$

Step3: Combine like bases

$2^{\frac{1}{3}} \cdot 2^{\frac{2}{3}} = 2^{\frac{1}{3}+\frac{2}{3}}$

Step4: Add the exponents

$\frac{1}{3}+\frac{2}{3}=1$, so $2^{1}=2$

Answer:

2