Question

simplify.
$\frac{y - 7}{y^2 - 14y + 49}$

Explanation:

Step1: Factor the denominator

The quadratic denominator is a perfect square trinomial:
$y^2 - 14y + 49 = (y - 7)^2$

Step2: Cancel common factors

Cancel the shared $(y - 7)$ term from numerator and denominator (note $y
eq 7$ to avoid division by zero):
$\frac{y - 7}{(y - 7)^2} = \frac{1}{y - 7}$

Answer:

$\frac{1}{y - 7}$ (where $y
eq 7$)