Question

solve $2x + 4 > 16$. \
\
\bigcirc a. $x > 6$ \
\
\bigcirc b. $x < 10$ \
\
\bigcirc c. $x < 6$ \
\
\bigcirc d. $x > 10$

Explanation:

Step1: Subtract 4 from both sides

To isolate the term with \( x \), we subtract 4 from both sides of the inequality \( 2x + 4 > 16 \). This gives us \( 2x + 4 - 4 > 16 - 4 \), which simplifies to \( 2x > 12 \).

Step2: Divide both sides by 2

To solve for \( x \), we divide both sides of the inequality \( 2x > 12 \) by 2. This gives us \( \frac{2x}{2} > \frac{12}{2} \), which simplifies to \( x > 6 \).

Answer:

A. \( x > 6 \)