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solve for $n_2$.\\ $\\dfrac{(n_1 - n_2)m}{4} = y$\\ $n_2 = \\square$

Question

solve for $n_2$.\\
$\dfrac{(n_1 - n_2)m}{4} = y$\\
$n_2 = \square$

Explanation:

Step1: Multiply both sides by 4

$$\frac{(n_1 - n_2)m}{4} \times 4 = Y \times 4$$
$$(n_1 - n_2)m = 4Y$$

Step2: Divide both sides by m

$$\frac{(n_1 - n_2)m}{m} = \frac{4Y}{m}$$
$$n_1 - n_2 = \frac{4Y}{m}$$

Step3: Isolate $n_2$

$$-n_2 = \frac{4Y}{m} - n_1$$
$$n_2 = n_1 - \frac{4Y}{m}$$

Answer:

$n_1 - \frac{4Y}{m}$