Question

solve.
\\(\frac{1}{3}s - 6 < 24\\)
\\(\circ \\{s\mid s < 6\\}\\)
\\(\circ \\{s\mid s < 10\\}\\)
\\(\circ \\{s\mid s < 54\\}\\)
\\(\circ \\{s\mid s < 90\\}\\)

Explanation:

Step1: Add 6 to both sides

To isolate the term with \( s \), we add 6 to both sides of the inequality \(\frac{1}{3}s - 6 < 24\). This gives us \(\frac{1}{3}s - 6 + 6 < 24 + 6\), which simplifies to \(\frac{1}{3}s < 30\).

Step2: Multiply both sides by 3

To solve for \( s \), we multiply both sides of the inequality \(\frac{1}{3}s < 30\) by 3. This gives us \( 3\times\frac{1}{3}s < 30\times3 \), which simplifies to \( s < 90 \).

Answer:

\(\{s\mid s < 90\}\)