Question

subtract.
$(6v^{2} - 5v - 9) - (3v^{2} - 3v - 4)$

Explanation:

Step1: Distribute the negative sign

To subtract the second polynomial from the first, we distribute the negative sign to each term in the second polynomial:
$$(6v^2 - 5v - 9) - 3v^2 + 3v + 4$$

Step2: Combine like terms

• For the \(v^2\) terms: \(6v^2 - 3v^2 = 3v^2\)
• For the \(v\) terms: \(-5v + 3v = -2v\)
• For the constant terms: \(-9 + 4 = -5\)

Putting it all together, we get:
$$3v^2 - 2v - 5$$

Answer:

\(3v^2 - 2v - 5\)