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subtract. $(9p^{2} + 3p + 4) - (p + 1)$

Question

subtract.
$(9p^{2} + 3p + 4) - (p + 1)$

Explanation:

Step1: Distribute the negative sign

To subtract the second polynomial, we distribute the negative sign to each term inside the parentheses:
$$(9p^2 + 3p + 4) - p - 1$$

Step2: Combine like terms

Now, we combine the like terms. The \(p^2\) term has no like terms, so it remains \(9p^2\). For the \(p\) terms: \(3p - p = 2p\). For the constant terms: \(4 - 1 = 3\).
Putting it all together, we get:
$$9p^2 + 2p + 3$$

Answer:

\(9p^2 + 2p + 3\)