Question

$x^2 - 25$
$(x-5)(x-5)$
$(x+5)(x+5)$
$(x+5)(x-5)$
prime

Explanation:

Step1: Recognize difference of squares

The expression $x^2 - 25$ is a difference of squares, which follows the form $a^2 - b^2$. Here, $a=x$ and $b=5$, since $x^2 = (x)^2$ and $25 = 5^2$.

Step2: Apply difference of squares formula

The difference of squares factors as $a^2 - b^2=(a+b)(a-b)$. Substitute $a=x$ and $b=5$.
$x^2 - 25=(x+5)(x-5)$

Answer:

$(x+5)(x-5)$